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abs (PHP 3, PHP 4, PHP 5) abs -- Wartość bezwględna (moduł z liczby) Opismixed abs ( mixed liczba )
Zwraca wartość bezwzględną (moduł) podanego argumentu
liczba. Jeśli argument jest typu
float, zwracana jest także wartość float,
inaczej zwracana jest wartość integer (float
ma zwykle szerszy zakres niż integer).
Przykład 1. przykłady abs() |
$abs = abs(-4.2); // $abs = 4.2; (double/float)
$abs2 = abs(5); // $abs2 = 5; (integer)
$abs3 = abs(-5); // $abs3 = 5; (integer)
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User Contributed NotesJosh
08-Jan-2006 01:06
Let's say you are resizing images to a standard size that can be expressed as a ratio (width/height). The problem I came into was that I wanted to be reasonable with the proportion of the images that my customer is uploading (couldn't we all use a little less horizontal on pictures?), but I wanted to reject the horizontal pictures when they were uploading vertical ones. So I wanted to accept proportions of images that were within a reasonable threshold (+ or -) of what I will be resizing them to.
Assuming a standard of 1 to 4 (0.25) and a threshold of no more than 0.05 deviation, then the number 0.30 and 0.20 would return true and 0.19 would return false.
<?php
function threshold($given,$thresh,$standard)
{
return (abs($given-$standard)<=$thresh) ? true : false;
}
?>
jeremys at hang dash wire dot com
12-Dec-2005 05:05
I'm unable to replicate concordia's problem with the $n = $n - $n * 2 code. I agree with the simplification to $n *= -1. But there's no reason that concordia's code should return 6 for the value -2, and it doesn't appear to. When I tried it, PHP returned 2, as it should. If PHP were somehow flipping the sign of integers randomly, that would be a *major* bug!
There doesn't seem to be a sgn() function yet. Here's some quick code to do it:
function sgn($x) {
return $x ? ($x>0 ? 1 : -1) : 0;
}
You could use $x ? abs($x)/$x : 0 too, but might as well avoid the float division.
Lazarus
12-Dec-2005 03:53
Even that is unnecessarily complex. Try this:
<?php
function n_abs($v) { return -abs($v) ; }
?>
Faster too.
rdk
10-Nov-2005 08:04
concordia, you seem to be overcomplicating matters. If you want to do the reverse of the abs function, the only code required is:
<?php
function n_abs($num) {
return ($num > 0) ? $num * -1 : $num;
}
n_abs(2); n_abs(-2); ?>
If you want to switch the sign bit of a number, as your example seems to indicate...
turn_neg (2); // -2
turn_neg (-2); // 2
...you just need to do $num *= -1;
Your function also doesn't seem to work. Switching "if (is_neg ($num))" to "if (!is_neg ($num))" would make it function as indicated by your comments (i.e. toggle the sign bit), but it would still be overly complicated.
concordia at game dot xakep dot org
06-Nov-2005 10:35
Sometimes you may want to do the opposite of abs(): turn a positive number into a negative.
<?php
function turn_neg ($num) {
return $num - $num * 2;
}
?>
But this can create errors when you put a negative number inside...
turn_neg (-2) returns 6.
<?php
turn_neg (-2); ?>
The solution is to make another function to determine if the number is negative or not.
<?php
function is_neg ($num) {
return $num < 0;
}
function turn_neg ($num) {
if (is_neg ($num)) {
return $num - $num * 2;
} else {
return abs ($num);
}
}
turn_neg (2); turn_neg (-2); ?>
Or, if the number is not negative, you could also return false.
alreece45 at yahoo dot com
10-Aug-2005 09:05
Both of the below codes were wrong.
<?php
if(!is_numeric($range)) {
$range=1;
}
if(!is_int($range)) {
$range=intval($range);
}
$range=abs($range);
?>
The only thing I don't get is why we have to check before doing the functions. Whether or not we do the functions it will give us what we want. The only check I really understand being there is the one that sets it to one.
Why not just do:
<?php
$range = is_numeric($range) ? abs(intval($range)) : 1;
?>
Seems like a lot less code. Or If you prefer to stay with if statements:
<?php
if(is_numberic($range)) {
$range = abs(intval($range));
}
else {
$range = 1;
}
?>
Both ways seem smaller to me.
abodeman at y a h o o
25-May-2004 02:59
There's another problem in the below code. The correct function to see whether a value is an integer is is_int(), not int(), so the code should look like this:
<?php
if(!is_numeric($range)){
$range=1;
}if(!is_int($range)){
$range=int_val($range);
}$range=abs($range);?>
mbender at duforu dot com
01-Mar-2004 10:59
bgustin AT trukfixer DOT com
16-Jul-2003 05:50
assume we take user input from a form untreated and assign it to variable $range. We want to be sure this number is a Positive Whole number, since abs() just sets a number to positive or 0, and we dont want decimals...
<?php
if(!is_numeric($range)){
$range=1;
}if(!int($range)){
$range=int_val($range);
}$range=abs($range);?>
for example the input "testing" would return $range =1,
the input "3.578" would return value=3
If the input is null, I am havent tested to see if it gets set to 1 courtesy of int_val or not, but I believe it will be.
I'm sure there's probably a more elegant way to do this using regex, however for an apprentice php coder, this might be a little easier to understand and use.
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