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W takich dniach, jak ten, nie żałuję, że wykupiłem abonament. Korzystam z porad na tych stronach nawet kilkanaście razy w tygodniu i dzięki nim prace nad stronami dla klientów idą mi o wiele szybciej, a strony wyglądają bardziej profesjonalnie. Nie wiem, jak mogłem wcześniej pracować bez dostępu do porad w tym serwisie!
Wojciech Miszkiewicz
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PODRĘCZNIK PHP 5.x, 4.x, 3.x - częściowo spolszczony / źródło: www.php.net
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count_chars (PHP 4, PHP 5) count_chars --
Return information about characters used in a string
Descriptionmixed count_chars ( string string [, int mode] )
Counts the number of occurrences of every byte-value (0..255) in
string and returns it in various ways.
The optional parameter mode defaults to
0. Depending on mode
count_chars() returns one of the following:
0 - an array with the byte-value as key and the frequency of
every byte as value.
1 - same as 0 but only byte-values with a frequency greater
than zero are listed.
2 - same as 0 but only byte-values with a frequency equal to
zero are listed.
3 - a string containing all used byte-values is returned.
4 - a string containing all not used byte-values is returned.
Przykład 1. count_chars() example |
<?php
$data = "Two Ts and one F.";
$result = count_chars($data, 0);
for ($i=0; $i < count($result); $i++) {
if ($result[$i] != 0)
echo "There were $result[$i] instance(s) of \"" , chr($i) , "\" in the string.\n";
}
?>
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This will output :
There were 4 instance(s) of " " in the string.
There were 1 instance(s) of "." in the string.
There were 1 instance(s) of "F" in the string.
There were 2 instance(s) of "T" in the string.
There were 1 instance(s) of "a" in the string.
There were 1 instance(s) of "d" in the string.
There were 1 instance(s) of "e" in the string.
There were 2 instance(s) of "n" in the string.
There were 2 instance(s) of "o" in the string.
There were 1 instance(s) of "s" in the string.
There were 1 instance(s) of "w" in the string. |
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See also strpos() and
substr_count().
User Contributed NotesEric Pecoraro
27-May-2005 04:31
<?php
$pass = '123456' ; $pass = '111222' ; req_unique($pass,3);
function req_unique($string,$unique=3) {
if ( count(count_chars($string,1)) < $unique) {
echo 'false';
}else{
echo 'true';
}
}
?>
Alex Gemmell
14-Feb-2005 07:03
Use: Great for checking for unique characters in a password.
I wanted to check that my website users, when registering a user account, chose a "valid" (not-so-easily-guessed) password.
One of the many checks was that the password must have 6 unique characters. I was tying myself in knots with all kinds of recursive array calling when I was offered this wonderful one line solution:
function check_password($password) {
#Have 6 unique characters
if (count(count_chars($password, 1)) < 6) return false;
#
# other checks returning false as necessary
#
#
return true;
}
I cannot claim this wonderful line for myself - a Mr Lynch suggested this to me. Thanks!
seb at synchrocide dot net
17-May-2004 12:08
After much trial and error trying to create a function that finds the number of unique characters in a string I same across count_chars() - my 20+ lines of useless code were wiped for this:
<?
function unichar($string) {
$two= strtolower(str_replace(' ', '', $string));
$res = count(count_chars($two, 1));
return $res;
}
echo unichar("bob"); echo unichar("Invisibility"); echo unichar("The quick brown fox slyly jumped over the lazy dog"); ?>
I have no idea where this could be used, but it's quite fun
mlong at mlong dot org
30-Jan-2002 01:27
// Usefulness of the two functions
<?php
$string="aaabbc";
$acount=substr_count($string,"a");
$counts=count_chars($string,0);
$acount=$counts[ord("a")];
$bcount=$counts[ord("b")];
?>
maotin at hongkong dot com
01-Feb-2001 02:04
Here are some more experiments on this relatively new and extremely handy function.
$string = 'I have never seen ANYTHING like that before! My number is "4670-9394".';
foreach(count_chars($string, 1) as $chr => $hit)
echo 'The character '.chr(34).chr($chr).chr(34).' has appeared in this string '.$hit.' times.<BR>';
#The result looks like
#The character " " has appeared in this string 11 times.
echo count_chars($string,3);
#The output is '!"-.034679AGHIMNTYabefhiklmnorstuvy'
echo strlen($string).' is not the same as '.strlen(count_chars($string, 3));
#This shows that '70 is not the same as 36'
As we can see above:
1)If you cares only about what is in the string, use count_chars($string, 1) and it will return an (associative?) array of what shows up only.
2) Either I misunderstood what the manul actually said, or it does not work the way it described: count_chars($strting, 3) actually returned a string of what characters are in the string, not a string of their byte-values (which is great because a string of numbers would be much harder to handle);
3)This is a short version of password checking: get the original string's length, then compare with the length of the string returned by count_chars($string,3).
$length_of_string = strlen($string);
$num_of_chars = strlen(count_chars($string, 3));
$diff = ($length_of_string - $num_of_chars);
if ($diff)
echo 'At least one character has been used more than once.';
else
echo 'All character have been used only once.;
Note that since $num_of_chars gives no information about the actual number of occurance, we cannot go any further by the same rationale and say when $diff =2 then 2 characters showed up twice; it might be 1 character showd up 3 times, we have no way to tell (a good tolerance level setter, though). You have to get the array and check the values if you want to have more control.
4) Final trick: now we have a primitive way to count the number of words in a string! (or do we have a fuction for that already?)
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