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phpversion

(PHP 3, PHP 4, PHP 5)

phpversion -- Gets the current PHP version

Description

string phpversion ( [string extension] )

Returns a string containing the version of the currently running PHP parser. If the optional extension parameter is specified, phpversion() returns the version of that extension, or FALSE if there is no version information associated or the extension isn't enabled.

Notatka: This information is also available in the predefined constant PHP_VERSION.

Przykład 1. phpversion() example


<?php

// prints e.g. 'Current PHP version: 4.1.1'

echo 'Current PHP version: ' . phpversion();



// prints e.g. '2.0' or nothing if the extension isn't enabled

echo phpversion('tidy');

?>

User Contributed Notes

25-Oct-2005 07:08


The version 4.3.10-16 does not "respect" the requiement for the above code. Use this fuction.



sample call:

if(!check_version(PHP_VERSION, "4.1.0") )

{

   echo 'Current PHP version: ' . PHP_VERSION . ' is too low for this code!<p>';

}



Function:

# Compares versions of software

# versions must must use the format ' x.y.z... ' 

# where (x, y, z) are numbers in [0-9]



function check_version($currentversion, $requiredversion)

{

   list($majorC, $minorC, $editC) = split('[/.-]', $currentversion);

   list($majorR, $minorR, $editR) = split('[/.-]', $requiredversion);

   

   if ($majorC > $majorR) return true;

   if ($majorC < $majorR) return false;

   // same major - check ninor

   if ($minorC > $minorR) return true;

   if ($minorC < $minorR) return false;

   // and same minor

   if ($editC  >= $editR)  return true;

   return true;

}

Willem
10-Oct-2005 01:02


A little more easier and compact ;)



<?

/**

 * bool phpversion2 ( string version )

 *

 * var version : user version of php needed to be compared to the server version of php,

 *                  must respect the correct format ' x.y.z ' where (x, y, z) are numbers in [0-9]

 */

 

function phpversion2 ($version = "5.0.5")

{

    // does the ' user php version ' have the right format ?

    if (preg_match("/(^\d+\.\d+\.\d+$)/", $version) == null)

    {

        return false;

    }

    

    if (str_replace(".", "", phpversion()) >= str_replace(".", "", $version))

    {

        return true;

    }

    

    return false;

}

?>

nick at divbyzero dot com
28-Jul-2005 10:06


Of course, if you want to COMPARE versions, you can't just compare them numerically, so try something like:



<?php 

echo phpversion()."\n"; //4.3.10-15

$v2 = preg_replace("/[^0-9\.]+/","",phpversion()); //4.3.1015

$v=$v2-0; // 4.3

$v2=substr($v2,strlen($v."")+1); //1015

echo $v." ".$v2."\n";



echo ($v>4.3 || ($v==4.3 && $v2>=1))."\n"; // 1 if >= 4.3.1

?>

ground-pilot at net-pilots.com
22-Jan-2005 08:52


Difference from bleeding edge server and production server where I couldn't use the phpversion() function. Came up with this to grab it from the command line instead. Note that the 'command line' version result , and 'http server api' version result could be two or more different versions, and not matching each other. So this may return a misleading value for your environment? Be careful if you have updated the web server api and not the command line, or visa-versa. ;)



But for me - it works. 



<?php

$PHP_VERSION = get_my_phpver();



echo "PHP_VERSION = $PHP_VERSION<br>";



function get_my_phpver() {

// USE :

//   $PHP_VERSION = get_my_phpver();

// CAVEAT NOTES :    

//   exec() will only return last line

//   passthru() will always show output, even when you ob_start() the output.

//   shell_exec() will return ALL lines of output but not forced

    $my_phpver = trim(substr(shell_exec('php -v'), 3, 6)); 

    // returns "4.3.1" of "PHP 4.3.1 (cgi)..." and removes white spaces

    return $my_phpver;

}

?>



Of course this would also do the trick...



<?php

$PHP_VERSION = trim(substr(shell_exec('php -v'), 3, 6));

echo "PHP_VERSION = $PHP_VERSION<br>";

?>



And as always, there are OTHER method, but this works for me. 



Hope this helps someone else out as well. :)