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OPINIE UŻYTKOWNIKÓW
Przyznam, że jestem pod sporym wrażeniem. Od wielu lat zajmuje się grafiką przeznaczoną do druku ze szczególnym uwzględnieniem opakowań. Z radością stwierdzam, iż twórca serwisu jest moim ulubionym typem potencjalnego współpracownika (choć branża troszeczkę inna) tzn. pada pytanie i błyskawicznie pada konkretna odpowiedź bez względu na stopień skomplikowania pytania. Gorąco polecam współpracę, gdyż macie pewność że nie zostaniecie potraktowani sloganami typu "oczywiście", "nie ma sprawy" tylko otrzymacie konkretną pomoc. Tak trzymać! Na pewno jeszcze nie raz skorzystam

Paweł
Studio Gama

   
GALERIA FOTOGRAFII
   
PODRĘCZNIK PHP 5.x, 4.x, 3.x - częściowo spolszczony / źródło: www.php.net

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Rozdział 13. Stałe

Stała jest identyfikatorem (nazwą) dla prostej wartości. Jak sama nazwa wskazuje, wartość ta nie może się zmieniać podczas działania skryptu (poza wyjątkami: __FILE__ i __LINE__). Domyślnie, przy stałych uwzględniana jest wielkość liter. Przyjęto, że stałe są pisane dużymi literami.

Nazwa stałej podlega takim samym zasadom jak każda inna w PHP. Prawidłowa nazwa stałej rozpoczyna się literą, znakiem podkreślenia ("_"), następnie mogą występować litery, cyfry lub znaki podkreślenia. Dobrze reprezentuje to takie wyrażenie regularne: [a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*

Notatka: Na nasze potrzeby, litery to a-z, A-Z, oraz znaki ASCII od 127 do 255 (0x7f-0xff).

Zakres stałej jest globalny.

Składnia

Możesz definiować stałą używając funkcji define(). Kiedy stała zostanie zdefiniowana, nie może być już zmieniona albo undefined.

Tylko skalarne typy danych (boolean, integer, double i string) mogą być zawarte w stałych.

Możesz użyć wartości stałej poprzez zwykłe użycie jej nazwy. Inaczej niż przy zmiennych, w stałych NIE powinieneś prepend stałej znakiem $. Możesz także użyć funkcji constant(), aby odczytać wartość stałej, której nazwa jest przekazywana dynamicznie. Użyj funkcji get_defined_constants() aby otrzymać listę zdefiniowanych stałych.

Notatka: Stałe i globlane zmienne są pisane inaczej, a to oznacza, że np. TRUE i $TRUE są różne.

Jeśli użyjesz niezdefiniowanej stałej, PHP przyjmuje, że chcesz użyć nazwy stałej samej w sobie. Zostanie wtedy wysłane ostrzeżenie. Użyj funkcji defined() jeśli chcesz się dowiedzieć czy stała jest zdefiniowana.

Różnice pomiędzy stałymi, a zmiennymi:

  • Stałe nie mają znaku dolara ($) przed nazwą;

  • Stałe mogą być definiowane oraz używane wszędzie bez zważania na zasady dotyczące zakresu ich dostępności;

  • Stałe nie mogą być redefiniowane lub undefined po tym jak raz zostały zdefiniowane; i

  • Stałe mogą zawierać tylko wartości skalarne.

Przykład 13-1. Definiowanie stałych

<?php
define
("STALA", "Hello world!");
echo
STALA; // wyświetli "Hello world!"
echo Stala; // wyświetli "Stala" i zgłosi ostrzeżenie
?>




User Contributed Notes

anj at aps dot anl dot gov
20-Dec-2005 05:42

It is possible to define constants that have the same name as a built-in PHP keyword, although subsequent attempts to actually use these constants will cause a parse error. For example in PHP 5.1.1, this code

   <?php
   define
("PUBLIC", "Hello, world!");
   echo
PUBLIC;
  
?>

gives the error

   Parse error: syntax error, unexpected T_PUBLIC in test.php on line 3

This is a problem to be aware of when converting PHP4 applications to PHP5, since that release introduced several new keywords that used to be legal names for constants.


kencomer at NOSPAM dot kencomer dot com
14-Sep-2005 02:38

Being a belt and suspenders person, when I use a constant to do flow control (i.e., using constants to determine which version of a section of the program should be used), I always use something like:

if ( defined('DEBUG') && TRUE===DEBUG )

If you accidentally use DEBUG somewhere before it is defined, PHP will create a new constant called DEBUG with the value 'DEBUG'. Adding the second comparison will prevent the expression from being TRUE when you did not intentionally create the constant. For the constant DEBUG, this would rarely be a problem, but if you had (e.g.) a constant used to determine whether a function was created using case-sensitive comparisons, an accidental creation of the constant IGNORE_CASE having the value 'IGNORE_CASE' could drive you up the wall trying to find out what went wrong, particularly if you had warnings turned off.

In almost all code I write, I put this function definition in my configuration section:

if (!function_exists("debug_print")) {
  if ( defined('DEBUG') && TRUE===DEBUG ) {
   function debug_print($string,$flag=NULL) {
     /* if second argument is absent or TRUE, print */
     if ( !(FALSE===$flag) )
       print 'DEBUG: '.$string . "\n";
   }
  } else {
   function debug_print($string,$flag=NULL) {
   }
  }
}

Then, in my code, I'll sprinkle liberal doses of debug code like :

define("DEBUG_TRACK_EXAMPLE_CREATION",FALSE);
class Example extends Something {
  __construct($whatever) {
   debug_print( "new instance of Example created with '$whatever'\n",DEBUG_TRACK_EXAMPLE_CREATION);
  }
}

and :

debug_print("finished init.\n")

In the first case, I would not want to see that message every time I went into DEBUG mode, so I made it a special case. The second case is always printed in DEBUG mode. If I decide to turn everything on, special cases and all, all I have to do is comment out the "if" line in debug_print() and presto magicko! It costs a little and gains a lot.

As another belt-and-suspenders aside, notice that, unlike most people, I put the language constant (e.g.,TRUE, "string", etc.) on the left side of the comparison. By doing that, you can never accidentally do something like
  if ( $hard_to_find_error="here" )

because you always write it as
  if ( "here"==$no_error )

or, if you got it wrong,
  if ( "here"=$easy_to_find_parse_error )


a dot eibach at gmx dot net
01-Sep-2005 11:11

It took me almost 30 minutes to find out what was wrong in my code. I thought I had defined all constants correctly: correct quotes, and whatnot.
The problem: I am a C programmer and I used #define with the preprocessor hash sign! No effect, naturally.
So if you happen to come from C world and you program PHP, *DO NOT* use the preprocessor hash as you're used to in C.


Angelina Bell
25-Jul-2005 09:39

It is so easy to create a constant that the php novice might do so accidently while attempting to call a function with no arguments.  For example:
<?php
function LogoutUser(){
// destroy the session, the cookie, and the session ID
 
blah blah blah;
  return
true;
}
function
SessionCheck(){
 
blah blah blah;
// check for session timeout
...
   if (
$timeout) LogoutUser// should be LogoutUser();
}
?>

OOPS!  I don't notice my typo, the SessionCheck function
doesn't work, and it takes me all afternoon to figure out why not!

<?php
LogoutUser
;
print
"new constant LogoutUser is " . LogoutUser;
?>


ck
27-May-2005 04:23

Re: Storm.
I ran that code (in PHP4)
<?php
if (DEBUG) {
  
// echo some sensitive data.
}
?>
and saw this warning:
"Use of undefined constant DEBUG - assumed 'DEBUG'"

A clearer workaround is to use
<?php
if (defined('DEBUG')) {
  
// echo some sensitive data.
}
?>
Thanks for pointing out this big gotcha.

Another reason to turn on warnings during testing.  Good web servers are set up to suppress warning and error output to the browser, so this is handy:
<?php
if (defined('DEBUG')) {
 
error_reporting(E_ALL);
 
set_error_handler('debug_ErrorHandler');
}
function
debug_ErrorHandler($errno, $errstr, $errfile, $errline) {
  print(
"PHP Error [$errno] [$errstr] at $errline in $errfile.<br>");
}
?>


hafenator2000 at yahoo dot com
21-Apr-2005 11:09

PHP Modules also define constants.  Make sure to avoid constant name collisions.  There are two ways to do this that I can think of.
First: in your code make sure that the constant name is not already used.  ex. <?php if (! defined("CONSTANT_NAME")) { Define("CONSTANT_NAME","Some Value"); } ?>  This can get messy when you start thinking about collision handling, and the implications of this.
Second: Use some off prepend to all your constant names without exception  ex. <?php Define("SITE_CONSTANT_NAME","Some Value"); ?>

Perhaps the developers or documentation maintainers could recommend a good prepend and ask module writers to avoid that prepend in modules.


storm
18-Apr-2005 06:54

An undefined constant evaluates as true when not used correctly. Say for example you had something like this:

settings.php
<?php
// Debug mode
define('DEBUG',false);
?>

test.php
<?php
include('settings.php');

if (
DEBUG) {
  
// echo some sensitive data.
}
?>

If for some reason settings.php doesn't get included and the DEBUG constant is not set, PHP will STILL print the sensitive data. The solution is to evaluate it. Like so:

settings.php
<?php
// Debug mode
define('DEBUG',0);
?>

test.php
<?php
include('settings.php');

if (
DEBUG == 1) {
  
// echo some sensitive data.
}
?>

Now it works correctly.


Charles
12-Jan-2005 10:50

To clarify from the previous post:

When you define a constant, it becomes fixed at that point and is immutable. You can add variables - but the constant becomes the contents of that variable when the define is evaluated. If you try:

define( "_A_TEXT" , "The value is " . $arr[$i] );

It would be evaluated ONCE with the current value of the $i index of array $arr. As the post pointed out, this is probably not what you want. You can easily create:

define( "_A_TEXT" , "The value is ");
....
echo _A_TEXT . $arr[$i];

Which would give you what you wanted: the constant string with the contents of the array appended.


the_coder at colina2004 dot com
24-Jun-2004 10:42

I'm currently working on a site that has got to have two languages, and I wanted to use define's in functions to make everything simpler.

However, I ran into a problem. PHP doesn't recognize the variable in:
define("constantName", "This is an array variable - {$array[$i][2]}");

I can't use that in a for cycle, like I wanted to:

for ($i = 0; $i < count($array); $i++) {
echo constantName . "<br />"
}

The method I found (I think it's been mentioned before) is to:

define("constantName", "This is an array variable - %s");

And then:

for ($i = 0; $i < count($array); $i++) {
printf(constantName, $array[$i][2]);
}


kumar at farmdev
26-Oct-2003 02:59

before embarking on creating a language system I wanted to see if there was any speed advantage to defining language strings as constants vs. variables or array items.  It is more logical to define language strings as constants but you have more flexibility using variables or arrays in your code (i.e. they can be accessed directly, concatenated, used in quotes, used in heredocs whereas constants can only be accessed directly or concatenated).

Results of the test:
declaring as $Variable is fastest
declaring with define() is second fastest
declaring as $Array['Item'] is slowest

=======================================
the test was done using PHP 4.3.2, Apache 1.3.27, and the ab (apache bench) tool.
100 requests (1 concurrent) were sent to one php file that includes 15 php files each containing 100 unique declarations of a language string.

Example of each declaration ("Variable" numbered 1 - 1500):
<?php
$GLOBALS
['Variable1'] = "A whole lot of text for this variable as if it were a language string containing a whole lot of text";
?>
<?php
define
('Variable1' , "A whole lot of text for this variable as if it were a language string containing a whole lot of text");
?>
<?php
$GLOBALS
['CP_Lang']['Variable1'] = "A whole lot of text for this variable as if it were a language string containing a whole lot of text";
?>

Here are the exact averages of each ab run of 100 requests (averages based on 6 runs):
variable (24.956 secs)
constant (25.426 secs)
array (28.141)

(not huge differences but good to know that using variables won't take a huge performance hit)


ewspencer at industrex dot com
18-Aug-2003 03:30

I find using the concatenation operator helps disambiguate value assignments with constants. For example, setting constants in a global configuration file:

define('LOCATOR',  "/locator");
define('CLASSES',  LOCATOR."/code/classes");
define('FUNCTIONS', LOCATOR."/code/functions");
define('USERDIR',  LOCATOR."/user");

Later, I can use the same convention when invoking a constant's value for static constructs such as require() calls:

require_once(FUNCTIONS."/database.fnc");
require_once(FUNCTIONS."/randchar.fnc");

as well as dynamic constructs, typical of value assignment to variables:

$userid  = randchar(8,'anc','u');
$usermap = USERDIR."/".$userid.".png";

The above convention works for me, and helps produce self-documenting code.

-- Erich


php-comment-2003-july-24 at ryandesign dot de
24-Jul-2003 04:04

Late reply to fmmarzoa at gmx dot net: You're better off using sprintf format and defining your strings like this:

define('strArticleDescr', 'Published by %1$s on %2$s in %2$s');

It's more standard than what you're doing. Then instead of outputting it using an eval, do this:

echo sprintf(strArticleDescr, $article_author, $article_date, $article_lang_name');

And even better for i18n and l10n, don't use defines; use gettext. See the PHP manual section on gettext and the GNU gettext website. Gettext requires some modification of the way you think about strings but I find it worthwhile to make that adjustment.


Mike Powell
25-Mar-2003 05:46

In response to the notes above about variable references in constants, double quotes isn't a proper solution because it parses the variable at the time the constant is defined. The desired behavior is to have the variables parsed at the time the constant is referenced, and this behavior can really only be achieved by using eval(), as described above.


gv (at) damnsw (dot) net
06-Nov-2002 05:08

fmmarzoa: In PHP 4.2.2/CLI, I had no problem setting define()'s to the contents of variables:

<?
   $foo
= "PHP";
  
define( "bar", "$foo is a good thing." );
   print
bar;
?>

Will print "PHP is a good thing.".

A notable difference, however, between my example and yours is your use of single-quotes.  Strings in single quotes (') will not be expanded:

print '$foo';

Will print '$foo', not the contents of $foo.

http://www.php.net/manual/en/language.types.string.php

--gv


alan at akbkhome dot com
23-Mar-2002 06:08

The __FILE__ constant in 4.2rc1 (CLI) will return the location of script specified to be run, rather than the absolute file.

eg. /usr/bin/phpmole (a softlink to /usr/lib/php/phpmole/phpmole.php)

started like this
bash#/usr/bin/phpmole
 
the line echo __FILE__ in phpmole.php will output /usr/bin/phpmole - in the CGI it would have returned /usr/lib/php/phpmole/phpmole.php

the workaround is to check for links!!
$f = __FILE__;
if (is_link($f)) $f = readlink($f);


katana at katana-inc dot com
25-Feb-2002 08:53

Warning, constants used within the heredoc syntax (http://www.php.net/manual/en/language.types.string.php) are not interpreted!

Editor's Note: This is true. PHP has no way of recognizing the constant from any other string of characters within the heredoc block.


afuse at yahoo dot com
11-Jun-2001 07:42

The pre-defined constant '__FILE__' does not work in same way at every version of PHP.

Some version of PHP has the relative path, and some other has the absolute path on __FILE__ constant..

Please be carefull in use..

[PS]
I have not tested at all versions of PHP but the version of 4.04pl.. and 4.05 are certainly not working in same way..  If you want to see that bug(?), I can show you an example.


silvein at sonique dot com
24-Jan-2001 02:54

It may be useful to note that, in php4 (what version this started I don't know, but it didn't do it before we upgraded to php4) __FILE__ will follow symlinks to the origional file.


tom dot harris at home dot com
05-Aug-2000 02:44

To get a full path (the equivalent of something like "__PATH__") use
dirname($SCRIPT_FILENAME)
to get the directory name of the called script and
dirname(__FILE__)
to get the directory name of the include file.


 

 
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