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OPINIE UŻYTKOWNIKÓW
Przyznam, że jestem pod sporym wrażeniem. Od wielu lat zajmuje się grafiką przeznaczoną do druku ze szczególnym uwzględnieniem opakowań. Z radością stwierdzam, iż twórca serwisu jest moim ulubionym typem potencjalnego współpracownika (choć branża troszeczkę inna) tzn. pada pytanie i błyskawicznie pada konkretna odpowiedź bez względu na stopień skomplikowania pytania. Gorąco polecam współpracę, gdyż macie pewność że nie zostaniecie potraktowani sloganami typu "oczywiście", "nie ma sprawy" tylko otrzymacie konkretną pomoc. Tak trzymać! Na pewno jeszcze nie raz skorzystam

Paweł
Studio Gama

   
GALERIA FOTOGRAFII
   
PODRĘCZNIK PHP 5.x, 4.x, 3.x - częściowo spolszczony / źródło: www.php.net

[Spis] [A] [B] [C] [D] [E] [F] [G] [H] [I] [J] [K] [L] [M] [N] [O] [P] [Q] [R] [S] [T] [U] [V] [X] [W] [Z]

XI. Klasy/Obiekty

Wstęp

Te funkcje pozwalają uzyskać informacje o klasach i ich egzemplarzach, obiektach. Możesz uzyskać informację o nazwie klasy do jakiej należy obiekt, a także jej właściwości i metody. Używając tych funkcji możesz dowiedzieć się nie tylko do jakiej klasy należy obiekt, ale także ustalić jego przodków (np. jaką klasę rozszerza klasa tego obiektu).

Wymagania

Do zbudowania tego rozszerzenia nie są wymagane żadne zewnętrzne biblioteki.

Instalacja

By używać tych funkcji, nie trzeba niczego instalować. Są one częścią jądra PHP.

Konfiguracja czasu wykonywania

To rozszerzenie nie definiuje posiada żadnych dyrektyw konfiguracyjnych w pliku php.ini.

Typy zasobów

To rozszerzenie nie posiada żadnych rodzajów zasobów.

Stałe predefinopwane

To rozszerzenie nie posiada żadnych stałych.

Przykłady

W tym przykładzie najpierw zdefiniujemy bazową klasę i jej rozszerzenie. Klasa bazowa opisuje normalne warzywo, czy jest jadalne czy nie oraz jego kolor. Podklasa Szpinak dodaje metodę pozwalającą go zagotować i drugą, która pozwala dowiedzieć się, czy jest zagotowany.

Przykład 1. classes.inc

<?php

// klasa bazowa wraz z jej właściwościami i metodami
class Warzywo {

   var
$jadalne;
   var
$kolor;

   function
Warzywo($jadalne, $kolor="zielony") {
      
$this->jadalne = $jadalne;
      
$this->kolor = $kolor;
   }

   function
czy_jadalne() {
       return
$this->jadalne;
   }

   function
jaki_kolor() {
       return
$this->kolor;
   }

}
// koniec klasy Warzywo

// rozrzesza klasę bazową
class Szpinak extends Warzywo {

   var
$ugotowane = false;

   function
Szpinak() {
      
$this->Warzywo(true, "zielone");
   }

   function
ugotuj() {
      
$this->ugotowane = true;
   }

   function
czy_ugotowane() {
       return
$this->ugotowane;
   }

}
// koniec klasy Szpinak

?>

Teraz możemy stworzyć dwa egzemplarze tych klas i wydrukować informacje o nich, włączając w to informacje o przodkach. Zdefiniujemy także kilka użytecznych funkcji, głównie po to by uzyskać ładny wydruk zmiennych.

Przykład 2. test_script.php

<pre>
<?php

include "classes.inc";

// funkcje użytkowe

function drukuj_wlasciwosci($obj) {
  
$tab = get_object_vars($obj);
   while (list(
$wlasc, $wart) = each($tab))
       echo
"\t$wlasc = $wart\n";
}

function
drukuj_metody($obj) {
  
$tab = get_class_methods(get_class($obj));
   foreach (
$tab as $metoda)
       echo
"\tfunkcja $metoda()\n";
}

function
przodkowie_klasy($obj, $klasa) {
   global $
$obj;
   if (
is_subclass_of($GLOBALS[$obj], $klasa)) {
       echo
"Obiekt $obj należy do klasy ".get_class($$obj);
       echo
", podklasy $klasa\n";
   } else {
       echo
"Obiekt $obj nie należy do podklasy $klass\n";
   }
}

// tworzymy 2 egzemplarze obiektów

$warzywko = new Warzywo(true, "niebieski");
$lisciaste = new Szpinak();

// wydrukujemy informację o obiektach
echo "warzywko: KLASA ".get_class($warzywko)."\n";
echo
"lisciaste: KLASA ".get_class($lisciaste);
echo
", PRZODEK ".get_parent_class($lisciaste)."\n";

// pokażmy właściwości warzywka
echo "\nwarzywko: Właściwości\n";
drukuj_wlasciwosci($warzywko);

// i metody liściastego
echo "\nlisciaste: Metody\n";
drukuj_metody($lisciaste);

echo
"\nPrzodkowie:\n";
przodkowie_klasy("lisciaste", "Szpinak");
przodkowie_klasy("lisciaste", "Warzywo");
?>
</pre>

Wartą odnotowania rzeczą w powyższym przykładzie jest to, że obiekt $lisciaste jest egzemplarzem klasy Szpinak która to jest podklasą klasy Warzywo, i tak ostatnia część powyższego skryptu pokaże na wyjściu:

[...]
Przodkowie:
Obiekt lisciasty nie należy do podklasy Szpinak
Obiekt lisciasty należy do klasy Szpinak, podklasy Warzywo

Spis treści
call_user_method_array --  Wywołuje metodę użytkownika zadaną z tablicą parametrów [przestarzałe]
call_user_method --  Wywołuje metodę użytkownika na zadanym obiekcie [przestarzałe]
class_exists -- Sprawdza czy klasa została zdefiniowana
get_class_methods -- Zwraca tablicę nazw metod danej klasy
get_class_vars --  Zwraca tablicę domyślnych właściwości klasy
get_class -- Zwraca nazwę klasy zadanego obiektu
get_declared_classes -- Zwraca tablicę z nazwami zdefiniowanych klas
get_declared_interfaces --  Returns an array of all declared interfaces
get_object_vars -- Zwraca tablicę asocjacyjną właściwości obiektu
get_parent_class -- Pobiera nazwę klasy przodka dla obiektu lub klasy
interface_exists -- Checks if the interface has been defined
is_a --  Zwraca TRUE jeżeli obiekt jest tej klasy, lub ta klasa jest jednym z jego przodków
is_subclass_of --  Zwraca TRUE jeżeli klasa jest jednym z przodków obiektu
method_exists -- Sprawdza czy metoda klasy istnieje



User Contributed Notes

Chris
26-Oct-2005 12:06

You could reformat your query to use the 'as colname'
<?  $db->query("select found_rows() as found_rows"); ?>


pascal dot poncet at netconsult dot com
13-Oct-2005 04:21

Subject: using "sql_calc_found_rows" in a MySQL query while exploiting result in a PHP db class object.

Hello,

There is a nice function in MySQL that allows to know how many records would have been returned if no "where" clause were set : SQL_CALC_FOUND_ROWS.

If you have create a db object to collect the returned lines, you will be a little perplex when trying to call the result of this function.

Why ?
Simply because the returned field's name is "found_rows()" and obviously it's not possible to call something like :

<?php $result->found_rows() ?>

...as it will try to acces a method, not a property !

Then, the only way to get the right result seems to be the use of a class function, like :

<?php
  $db
->query("select found_rows()");
 
$count=current(get_object_vars(current($db->result)));
?>

Of course, if somebody found an other way to solve it, like a special syntax (see the one used with curled arrays in a string), I'm really open to discuss.

Good luck,
Pascal


ia [AT] zoznam [DOT] sk
03-Aug-2005 07:55

as for zabmilenko's solution:
wouldn't it be better to create it this way?

<?php
// The base class for all db classes
class DB {
 
protected $connectId;
}

// Class for MySQL, which extends base class
class MySQL extends DB {
 function
connect () {
 
$this->connectId = mysql_connect (...);
 }
}

// Class for PostgreSQL, which extends base class
class pgSQL extends DB {
 function
connect () {
 
$this->connectId = pg_connect (...);
 }
}

// and then call constructor like this:
$dbName = "MySQL";
$db = new $dbName ( ... );
// ... which creates an object of class MySQL
?>


zabmilenko at hotmail dot com
27-Jun-2005 09:08

((PHP5))

I wanted to dynamically choose an extender for a class.  This took awhile of playing with it but I came up with a solution.  Note that I can't verify how safe it is, but it appears to work for me.  Perhaps someone else can shed light on the details:

<?php

class A { var $value = "Class A\n"; }
class
B { var $value = "Class B\n"; }

// Uncomment which extender you want.  You can use variables as well.
// define('__EXTENDER__', 'A');
  
define('__EXTENDER__', 'B');

// Use eval to create a wrapper class.
eval('class EXTENDER extends '. __EXTENDER__ . ' { }');

class
C extends EXTENDER
{
  function
__construct()
  {
     echo
$this->value;
  }
}

$t = new C;

?>

Outputs:  Class B

Practical application:  I have a database abstraction system that has individual classes for mysql, pgsql, et al.  I want to be able to create a global db class that extends one of the individual db classes depending on the application configuration.

I know that there are probably much better ways of doing this but I haven't reached that level when it comes to classes.


cjones
03-Mar-2005 10:27

If anyone is interested in looking for a way to dynamically load existing objects into a class, here is what I found very useful.

//---------------------------------------------------------
// Dynamically load External Objects into a class

  function objRef ( &$obj ) {   
   eval("\$this->obj_".get_class($obj)." = \$obj;");
  }
//---------------------------------------------------------
// Reference by using: $this->obj_[object Name]->[var|f{}]

Example:

class date {  function date ( ) { $this->date = "March 3rd"; } }
class time {  function time ( ) { $this->time = "12:30pm"; } }

class show {
   function objRef ( &$obj ){
       eval("\$this->obj_".get_class($obj)." = \$obj;");
   }
   function test ( $var ){
       echo "$var".$this->obj_date->date." @ ".$this->obj_time->time;
   }
}

$date = new date;
$time = new time;
$show = new show;
   $show->objRef($date);
   $show->objRef($time);
   $show->test("Time Now => ");

// Output: Time Now => March 3rd @ 12:30pm

I found the prefix 'obj_' before the class name useful because it helped me to automatically identify external object references when scanning through my scripts. You can omit this if you want. Hope this helps someone.


http://sc.tri-bit.com/ StoneCypher
02-Mar-2005 07:25

to covertka at muohio dot edu and pillepop2003 at yahoo dot de:

There's a much easier solution to getting a class' name for working with a factory function.  Let's assume you're doing something like this:

<?php

 
function FactoryFunction($whatever, $instancedata) {

   switch (
$whatever) {
     case
'stuff'      : return new Stuff($instancedata);
     case
'otherstuff' : return new Otherstuff($instancedata);
   }

  }

?>

Now, consider the named parameter idiom and remember that PHP uses hashes for everything; as a result make the following changes:

<?php

 
function FactoryFunction($whatever, $instancedata) {

   switch (
$whatever) {

     case
'stuff'      : return array('typeis'=>'stuff',      'instance'=>new Stuff($instancedata));
     case
'otherstuff' : return array('typeis'=>'otherstuff', 'instance'=>new Otherstuff($instancedata));

   }

  }

?>

Nice 'n simple.  It seems that what the original poster wanted was something like C++ static data members; unfortunately as PHP4 has no static variables at all, there would need to be significant language change to support static-like behavior.  If you move to PHP5, the static keyword solves your problem cleanly.


covertka at muohio dot edu
03-Jan-2005 02:27

To pillepop2003 at yahoo dot de:

I have the same issue.  I have a base class that manages database tasks for a number of child classes.  One of the functions in the base class is a find() method that returns instances of the child classes.  Since find() is usually called as a static method, it needs to know the name of the child class.  As you've found, this appears to be impossible to get in an easy fashion.

The only way I've found to get the child class name is to use the debug_traceback() function.  This requires me to have a find() method in every child class, but it does work.

Here's an example:

<?php
 
require_once("Application.php");

  class
parentClass {
   function
find() {
    
$className = NULL;
     foreach (
debug_backtrace() as $bt) {
       if (
$bt['function'] == __FUNCTION__) {
        
$className = $bt['class'];
       }
     }

    
// here should be some code to find the proper id, let's assume it was id 1
    
$id = 1;
     return new
$className($id);
   }
  }
 
  class
foo extends parentClass {
   function
__construct($id) {
    
$this->id = id;
   }
  
   function
find() {
     return
parent::find();
   }
  }
 
  class
bar extends parentClass {
   function
__construct($id) {
    
$this->id = id;
   }

   function
find() {
     return
parent::find();
   }
  }
 
 
$a = foo::find();
 
printf("Type for \$a: %s<br/>\n", get_class($a));
 
$b = bar::find();
 
printf("Type for \$b: %s<br/>\n", get_class($b));
?>


iparanoid at gmx dot de
04-Aug-2004 08:17

To pillepop2003 at yahoo dot de:

It seems to me if there really is no nice way to get the class name in an un-instanciated class, there is a workaround in PHP5 though using static/class variables.

Example:

<?php

class myFoo
{
   static
$__ClassName = __CLASS__;

   static function
getClassName()
   {
       return
myFoo::$__ClassName;
   }
};

class
myFooExtended extends myFoo
{
   function
__construct()
   {
      
myFooExtended::$__ClassName = __CLASS__;
   };
};

?>

However, you'll need to have at least instanciated an object of the class myFooExtended before calling getClassName or introduce some other initialization (the class variable will need to be set at some point to __CLASS__ in the sub-class).


greg at doutromundo dot com
06-Jul-2004 04:58

As programmers, you're probably more organized than me, but, I do try and maintain some order in my classes and codes and separate them in "packages" as in java.
This helped me keep them organized but caused havok when trying to use them, so what I did was to create a class that handles the loading of classes (which I instanciate in all pages) along with my error handling class all bundled up. This way, I can load my classes with a command similar to
$baseClass->loadClass("package","className"[,"constructor"]);

the function responsible for this has some checking to see if they are loaded and stuff like that...

function loadClass($packageName,$className,$constructor=""){
  // if you dont have a constructor declare any function inside
  // the class
  if ($constructor==""){
   $constructor=$className;
  }
  if(!is_callable(array($className,$constructor))){
   if (defined("CLASS_DIR")){
     $pkg = CLASS_DIR.$packageName."/";
       if (is_dir($pkg)){
         // we have a directory with the package name
         $cls = $pkg.$className.".class.php";
         if(is_file($cls)){
           // we have a file
           include_once($cls);
         }else{
           die("Class <b>$className</b> could not be found in package <b>$packageName</b> , please check your instalation");
         }
       }else{
         die("Package <b>$packageName</b> could not be found, please check your instalation");
       }
     }
   }
}

Just remember to define CLASS_DIR as the physical path for the directories where you packages are...

Hope this comes in handy...

Here's an example of a diretory strucutre...
/var/www/classes/  <- this would be CLASS_DIR
in there I have:
package1/
     name.class.php
     name2.class.php
....

The loadClass would look like: loadClass("package1","name");

Cute and easy


ettinger at consultant dot com
19-Jun-2004 01:59

Re: Looking for an uninstantiated class

# Loads data from a table into a class object
class LFPDataFactory extends LFPObject {
       var $object;
       var $class;
       var $table;
       function LFPDataFactory($args) {
               $this->unpackArgs($args); // assigns locals from $args
               if (in_array(strtolower($this->class), get_declared_classes())) {
                       $this->object = new $this->class;
                       // assemble the columns in the table...
                       // select their values and put them in our new object...
               } else { trigger_error("Class ".$this->class." not found", E_USER_ERROR); }
       }
}
$r = new LFPDataFactory("class=LFPLayout,table=layout");
$new_obj = $r->object; // this is a LFPLayout object.
print_r($new_obj);

This class looks to see if the class exists, then instantiates it -- a declared class is not the same as an instantiated class. As long as LFPLayout exists somewhere in the scripts, get_declared_classes() will find it. Remember strtolower on compare, however.

Why would I do this? Because I have my class layouts the same as their respective tables; the factory then selects the data (making sure that the variables match) and plugs in the data. (I've left out the actual code to do the selection/insertion).


brett_hegr xATx yahoo xDOTx com
10-Jun-2004 02:46

// Useful function for determining if an object is either an
// instance or a subclass of a particular class.
function is_class($object,$class_name)
{
  $parent = is_a($object, $class_name);
  $child = is_subclass_of($object, $class_name);
  return $parent xor $child;
}


HOC
28-May-2004 06:40

to pillepop2003

Why do u want to know the classname of an non-existant object?

The only possible explanation for this question seems to me u want to know the class before u instantiate the object. Well, this is of no use since u always instantiate a class of ur choice.

When the class is instantiated into an object u can find the class of the object by means of get_class(). This is all u need. In case of inheritance u can use get_class($this) to get the class of the instantiated object. Now u can differentiate according to which class the object belongs to.

e.g.:

<?php
class A{
   function
A(){
    
$class_of_this = get_class($this);
     echo
'Object is an instance of class '.$class_of_this.' which is the ';
     if(
strcmp($class_of_this,'A')==0)
         echo
'parent-class';
     else if(
strcmp($class_of_this,'B')==0)
         echo
'child-class';
     echo
".\n";
   }
}

class
B extends A{
   function
B(){
    
$this->A();
   }
}

$object1 = new A();
$object2 = new B();
?>

When u run this code-snippet the output will be:

Object is an instance of class A which is the parent-class.
Object is an instance of class B which is the child-class.


mfirat at fibronline dot com
02-Apr-2004 03:18

<?php
  
class calculator {
     var
$c;
   function
addition($a, $b) {
      
$this->c = $a + $b;
       return
$this->c;
   }
      
   function
subtraction($a, $b) {
      
$this->c = $a - $b;
       return
$this->c;
   }
      
   function
multiplication($a, $b) {
      
$this->c = $a * $b;
       return
$this->c;
   }
      
   function
division($a, $b) {
      
$this->c = $a / $b;
       return
$this->c;
   }
 }

$cc = new calculator;
echo
$cc->addition(20, 10)."<br>";
echo
$cc->subtraction(20, 10)."<br>";
echo
$cc->multiplication(20, 10)."<br>";
echo
$cc->division(20, 10)."<br>";
?>


Fasoro Oladipo <dipofasoro at yahoo dot co dot uk>
14-Mar-2004 06:49

<?php
/*
[Why Not Use Classes]

Since PHP is object oriented OOP. Use it's features to the maximum.
 You can define ur business logic, data logic encapsulated in classes.
  For people who are not OOP,you might be wondering why this is needed.
   it is for code clarity, reusability, portability, ease of maintenace.
   Let's say for example, your site does a Login, Register, Feedback,
   Update, UnRegister and u are using a Informix database server.
You can */

//file user.php
class user {
   var
$dbconn
  
function user() {
      
//do initialisation
      
$this->dbconn = DB::getInformix();
   }
   function
Login($uname, $pass) {
      
//do login on uname and pass on Informix Server
       //run SQL queries on the Server
  
}
   function
Register($uname, $pass, $name, $email) {
      
//do register by running SQL Queries on Informix Server
  
}
   function
FeedBack($name, $email, $msg) {
      
//add feedback to informix server by running sql_queries
  
}
   function
Update($name, $email) {
      
//update name, email on Informix Server
  
}
   function
UnRegister() {
      
//delete user account from the informix server
  
}
}

//file template.php
class template {
   function
showlogin() {
      
//show the login interface
  
}
   function
showwelcome() {
      
//show welcoime when the person is logged in
  
}
}

//file DBs.php
class DB {
   function
getInformix() {
      
//get informix database conn
  
}
   function
getMySQL() {
      
//get MySQL conn
  
}
   function
getPostGRESQL() {
      
//get  PostGRESQL
  
}
}
/*
the file user will be included in all pages that can do a login or reg.
To get an informix database connection call DB::getInformix();
all username, server, password everything is handled in there.
Now the cue is to do login you just*/
$usr = new user();
$usr->Login($_POST["uname"], $_POST["pass"]);
//to do a register the same too is applied.
$usr->Register($_POST["uname"], $_POST["pass"], $_POST["name"], $_POST["email"]);
/* and so on..
all the logic of validation ands inserrting into the database is (login/register)
is done behind the bars of the class
to show the login interface you call template::showLogin()
You might have been wondering then what is new.
Consider if you want to change the login interface and the login has been declared
in 20 pages differently, it will be hard to add a [Forgot Password] link at the
bottom of the submit button. but if it were to be declared as a class function
just change the look in template::showLogin() and it will reflect in the 20 pages
immdeiately.
Consider again that you want users to specify that if they try to login from that
particular system IP address. They should be automatically logged in without
showing login interface. You can just extend the function to add an extra parameter */
Login($uname, $pass, $rememberIP);
/*and add a checkbox to template::showLogin(); call */
$usr->Login($_POST["uname"], $_POST["pass"], isset($_POST["remeberIP"]);
/*
and in the function interface you change your business logic to accomodate the
new parameter to taste.
Now let's say you just assume you connect to the informix database in 35 places
in your site and you want to change the login password to database. just chasnge
it in DB::getInformix(); and it will be reflected in the 35 pages if all of them
call DB::getInformix(). This will have saved u a headache of Search/Replace in
35 pages if you have connected explicitly in all the pages.
Another main issue is your IT manager comes the next morning and tells you that
he has heard that MySQL is now the bomb and wants a Database server change
to mySQL without the site getting down. if you are the wise one like me just
change $this->dbconn in the user class to DB::getMySQL(); in the constructor.
if u are not as wise. i am very sure this will give you at least a week long
HeadAche.

[Why Not Use Classes] is presented by Fasoro Oladipo, in Nigeria.
Fasoro Oladipo is a staunch advocate of OOP.
Thanks for reading this text, hope you have a change of mind.
*/
?>


ar at 5mm de
28-Aug-2003 04:59

I missed some kind of function to dynamicly override or extend an Object:

-----------------------------------------
function &extendObj(&$obj, $code) {
   static $num = 0;
  
   $classname = get_class($obj);
   $newclass = $classname.$num;
  
   eval('class '.$newclass.' extends '.$classname.' { '.$code.' }');
  
   $newobj = new $newclass();

   $vars = get_class_vars($classname);
   foreach($vars AS $key=>$value) {
       $newobj->$key = &$obj->$key;
   }
  
   return $newobj;
}
-----------------------------------------

This creates a new class which extends the old one by the given code parameter, instanciates it and copy all vars from the old obj to the new one.

-----------------------------------------
class testA {
   var $prop = 'a';
  
   function funcA($val) {
       $this->prop = $val;
   }
  
   function value() {
       return $this->prop;
   }
}

$obj = new testA();

$newobj = &extendObj(&$obj, 'function addX() { $this->prop .= "x"; }');

$newobj->funcA('abc');
$newobj->addX();
echo $newobj->value();
-----------------------------------------

Results in 'abcx'. You can use the function multiple times and also with class variables. Be carefull, even if $newobj is just a copy of $obj, $obj->value() will return 'abcx', too, because of the & operator: $newobj->$key = &$obj->$key;


zidsu at hotmail dot com
08-Jul-2003 02:24

FYI: if you want to split your class into manageble chunks, what means different files for you, you can put you functoins into includes, and make include() have a return value. Like this:

class Some_class {
  var $value = 3;
  function add_value ($input_param) {
   return include ("path/some_file.php");
  }
}

And your included file:

$input_param += $this->value;
return $input_param;

Then your function call will be:

$instance = new Some_class ();
$instance->add_value (3);

And this will return
6
hopefully :P

Keep in mind though, that the scope in the included file will be identical to the scope the function 'add_value' has.
And if you want to return the outcome, you should also have a return statement made in your include as well.


asommer*at*as-media.com
20-Sep-2002 11:52

Something I found out just now that comes in very handy for my current project:

it is possible to have a class override itself in any method ( including the constructor ) like this:

class a {

..function ha ( ) {
....if ( $some_expr ) {
......$this = new b;
......return $this->ha ( );
....}
....return $something;
..}

}

in this case assuming that class b is already defined and also has the method ha ( )

note that the code after the statement to override itself is still executed but now applies to the new class

i did not find any information about this behaviour anywhere, so i have no clue wether this is supposed to be like this and if it might change... but it opens a few possibilities in flexible scripting!!


einhverfr at not-this-host dot hotmail dot com
14-Sep-2002 09:35

You may find it helpful in complex projects to have namespaces for your classes, and arrange these in a hierarchical manner.  A simple way to do this is to use the filesystem to order your hierarchies and then define a function like this:

function use_namespace($namespace){

require_once("namespaces/$namespace.obj.php");

}

(lack of indentation due to HTML UI for this page)
This requires that all your object libraries end in .obj.php (which I use) but you can modfy it to suit your needs.  To call it you could, for exmaple call:

use_namespace("example");
or if foo is part of example you can call:
use_namespace("example/foo");


justin at quadmyre dot com
19-Aug-2002 06:38

If you want to be able to call an instance of a class from within another class, all you need to do is store a reference to the external class as a property of the local class (can use the constructor to pass this to the class), then call the external method like this:

$this->classref->memberfunction($vars);

or if the double '->' is too freaky for you, how about:

$ref=&$this->classref;
$ref->memberfunction($vars);

This is handy if you write something like a general SQL class that you want member functions in other classes to be able to use, but want to keep namespaces separate. Hope that helps someone.

Justin

Example:

<?php

class class1 {
   function
test($var) {
      
$result = $var + 2;
       return
$result;
   }
}

class
class2{
   var
$ref_to_class=''; # to be pointer to other class

  
function class1(&$ref){ #constructor
      
$this->ref_to_class=$ref; #save ref to other class as property of this class
  
}

   function
test2($var){
      
$val = $this->ref_to_class->test($var); #call other class using ref
      
return $val;
   }
}

$obj1=new class1;
# obj1 is instantiated.
$obj2=new class2($obj1);
# pass ref to obj1 when instantiating obj2

$var=5;
$result=obj2->test2($var);
# call method in obj2, which calls method in obj1
echo ($result);

?>


a2zofciv2 at hotmail dot com
29-Sep-2001 07:10

I spent 20 minutes or so trying to figure this out, maybe someone else has the same problem.

To access a class' function from within the class you would have to say $this->functionname(params), rather than just functionname(params) like in other programming languages.

Hope this helps


gateschris at yahoo dot com
08-Mar-2001 10:59

[Editor's note: If you are trying to do overriding, then you can just interrogate (perhaps in the method itself) about what class (get_class()) the object belongs to, or if it is a subclass of a particular root class.

You can alway refer to the parent overriden method, see the "Classes and Objects" page of the manual and comments/editor's notes therein.]

There is no function to determine if a member belongs to a base class or current class eg:

class foo {
 function foo () { }
 function a () { }
}

class bar extends foo {
 function bar () { }
 function a () { }
}

lala = new Bar();
------------------
how do we find programmatically if member a now belongs to class Bar or Foo.


 

 
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